100/5 = 20. Therefore 20 is the average, and therefore the middle day. The other days need to balance eachother.
Day 1 - 8
Day 2 - 14
Day 3 - 20
Day 4 - 26
Day 5 - 32
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Total - 100A cat ate 100 rats in 5 days, each day eating 6 more than on the day before.?
100 = x + (x+6) + (x+12) + (x+18) + (x+24)
100 = 5x + 60
40 = 5x
8 = x
Day 1: 8
Day 2: 14
Day 3: 20
Day 4: 26
Day 5: 32
The First Day the cat ate 8
The second day the cat ate 14
the third day the cat ate 20
the fourth day the cat ate 26
the fifth day the cat ate 32....
100 Mice in Five Days!
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